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Special => Roulette Lab => Topic started by: French_cunning_Fox on Jun 15, 2026, 05:52 PM

Title: Snowball progression from Sextius 1875
Post by: French_cunning_Fox on Jun 15, 2026, 05:52 PM
Hello my friend!
know you name Spanish Garcia? I presume yes, all Roulette Gamer know it's name!
Garcia progression was 1/3 and if lose it should bet 2/3 from it's betting value.
So is sure, with so progression, the gamer can only have lost 1x but on second essay, it should win. Or it lost heavy money.
Garcia, use divided Betting money from Full capital.

And now Snowball Progression from (pseudonym) Sextius (is a small town in South France, name done from Romanian General...).

So he divided his initial bankroll for the game by 10.
For example, the player needed a bankroll of $1,000, which had to be divided by 10; thus, he already had a bankroll of 10 × $100.
Then the player divided that bankroll by 20 to get $5, which would be the initial bet.
So, regardless of the system you use, the progression is 4x: you must win that $5 to get $20, and  here 120$/20 = 6$ as new Gaming bet, which you should win 4x. with 24$ Gain, you use only +20 so 120+20$ = 140, and the old +4$ going in pot to later...
with 140/20 =7$ Gaming Bet...
And here, to understand it better, I should you done table to play progression wait just a bit...
Title: Re: Snowball progression from Sextius 1875
Post by: French_cunning_Fox on Jun 16, 2026, 03:06 AM
(https://rouletteideas.com/proxy.php?request=http%3A%2F%2F%5Burl%3D%26quot%3Bhttps%3A%2F%2Fibb.co%2F0j7krz04%26quot%3B%255D%255Bimg%255Dhttps%3A%2F%2FI.ibb.co%2FccBPQsWf%2F1a27coup.jpg&hash=fa013c2a0b62e850253650a520c0c701d403b165)[/url][/img]1a27coup.jpg

Ok sorry it are first time to send picture on this forum, so I don't know if have succes!
So I think all gamer know about this!
The "1" beat occurs every 2 beats. or the intermittence pattern or Series or Serial!
Same the series of 2, coming each 4 beat, as example a series from 2 Red or 2 Black, or 2 Even ..., or 2 (1-18 or 19-36)
And a serie from 27 = 134,217 728 beats waiting...

occurs every beats.
Or, the interval pattern is also equal to the number of possible combinations.
So is possible on 500 beats/day play per Croupiers from Casino, in 9-11 hours of works, so that is coming out a serial of 9 Red or 9 Black or intermittence R-B-R-B... because this appear ~ each 512 Beats. But this is medium value.
Title: Re: Snowball progression from Sextius 1875
Post by: French_cunning_Fox on Jun 16, 2026, 03:38 AM
Each move or beats creates as many figures as the moves listed above;
that is, the move of 1 creates two figures: 1 red and 1 black;
the move of 2 creates four, and so on. This is what is known as the decomposition of moves.

so as on this picture.fig1-2.jpg
Left side = Figure or combinaison to 1 = 2 = Black or Red
Right = Figure or combinaison possibility to 4. = Bl-Bl or Bl-R or R-R or R-Bl.
And so to win 50% of combinaison, here don't play the first of party, so as party should from 4 beats or move by knowledge if this are Black or Red Side as Mastress Figure, so only is to play 3x second, third and 4. have you understand so is Better?
Title: Re: Snowball progression from Sextius 1875
Post by: French_cunning_Fox on Jun 16, 2026, 07:40 AM
But don't Forget, on minimal and maximum Roulette Table Bet Limit.

A Practical Method
To win Over 200,000 Francs in 1 Year

SPECULATION STRATEGY

FOR TRENTE ET QUARANTE & ROULETTE

Starting Capital: ONE THOUSAND FRANCS (Today $,€ or Fr.Suisse...)

INSTRUCTIONS

When putting into practice the system we are about to describe—whose main merit is to risk little to win much—one must not forget that in a speculation of this kind, capital, discipline, and perseverance are the key elements of success.

Any speculator who possesses enough composure,calmness, and strong will to be able to continue this operation without flinching, without wavering, without allowing himself to be discouraged or disheartened by the setbacks he may encounter, will be certain to succeed sooner or later; if not with the first capital of one thousand francs, it will be with the second, the third, or the fourth.
Title: Re: Snowball progression from Sextius 1875
Post by: French_cunning_Fox on Jun 16, 2026, 07:53 AM
By continuing with consistency, he will be in the same position to succeed as the bank,
which, despite these fluctuations and occasional spikes, always ends up making a certain profit at the end of the year. — The same will be true for the speculator who continues this game with confidence and perseverance.

See below the table, the explanation, and the probability proved by calculation.
Title: Re: Snowball progression from Sextius 1875
Post by: French_cunning_Fox on Jun 16, 2026, 08:24 AM
So here the Table of Progression.
boule.jpg
and here my translation from Text.

TABLE

EQUAL-STAKE GAME, THE SNOWBALL
FOR PLAYING
TRENTE ET QUARANTE
or
ROULETTE

A capital of 100 francs yields
2,460 francs in profit in ten days.
The table shows Each Column contain Word to value:

Séances = Session

Capital = Capital

Divisé = Divided by
par

Mises = Bets

Multipl. = Multiplier by
par

Bénefice = Profit

Réserve = Reserve.
Title: Re: Snowball progression from Sextius 1875
Post by: French_cunning_Fox on Jun 16, 2026, 02:46 PM
So here start explain from Author:

EXPLANATION

At the beginning, ten capitals of a hundred francs are needed, that is to say, a thousand francs.
We start with a capital of one hundred francs, which is divided by twenty, which gives twenty
bets of 5 fr. to play, (see the first first sitting)

The first session is therefore played at the time of the francs for the same mass, without paroli or progress always 5 francs, until we have four pieces of profit, or twenty francs, and they immediately withdrew.
These twenty francs earned are added to the capital of a hundred francs, which brings it to one hundred and twenty francs,

But here I stop it, because this was so learn in year 1875, so is sure in logical way, yes this is so good, but I self, I like play game or bet Game with only gain from Bank Casino.
So as: Here the Gamer need to win first 100$ So as Capital +120$ before it go to second step.
I am Sure, you know starting count of Progression. 1-1-2-3-4... not 1-2-3-4...
So player need to win, with 5$ bet 5x time 20$ = 100$ + 1x 20$ to are able to go to Step 2.
In  year 1875, is don't known the way to play, with only casino Gain, only ~1930 German Fritz Werntgen, have invented the Unloseable progression, and before all are from this type progression.

— which makes twenty bets of six francs, — we play
then the second session at the stake of six francs,
always with equal mass, and one withdraws in the same way
when you have four profit bets, I.e. 24
francs.
The fraction is stored in addition to
twenty, or the four francs that will be used to
the amortization of the capital, and we add
.20 fr. with a capital of 120 which brings it to 140, I.e.
twenty bets of 7 francs, and the third is played*
session at the 7 fr. still at the mass, on
equal stake.
We retire in the same way when we have four E
profit that is always added to the capital
minus the fractions of twenty that are put
in reserve, and the operation is thus continued
until the twentieth meeting, as indicated by
the painting.
In short, after each session we add
his capital gain, which thus increased, and being
always divided by 20, gives each time
Higher bets or masses to play during the session
— this is what is called, to make a ball
of snow.
If in a session you lose your twenty bets,
without being able to win his four pieces,
then we jumped from his first capital, a hundred
francs, less reserves; "Then we recommend
with a second capital of one hundred francs,
with which one operates in the same way, and so on.
We do at least two sessions a day, one
in the morning and one in the evening — so by winning
four progressive masses per session for
ten days, the primitive capital of these will have
reached the figure of:
Title: Re: Snowball progression from Sextius 1875
Post by: FreeRoulette on Jun 16, 2026, 06:31 PM
Am I understanding this right?

The 1875 Snowball System
Divide your bankroll into 20 equal betting units.

Example:

Starting bankroll: $100
Bet size: $100 ÷ 20 = $5 per bet
Flat bet $5 until your net profit equals 4 betting units.

Example:

$5 × 4 = +$20 profit goal

If successful:

$100 bankroll + $20 profit = $120 new bankroll
Calculate the new bet size.
$120 ÷ 20 = $6 per bet

Play $6 flat until your net profit reaches:

$6 × 4 = +$24 profit goal

If successful:

Add the $20 increase to your working capital:
$120 → $140
Place the extra $4 into reserve.
Repeat the process.

Each successful session:

Increase the working bankroll by $20
Increase the bet size (bankroll ÷ 20)
Put any profit above $20 into reserve
Important Failure Rule

If you lose all 20 betting units before reaching the profit goal:

Example:

$200 bankroll
$10 bets
Lose 20 bets = lose the entire $200 capital

That session is considered a failure. The original system says to start over with a fresh $100 capital, while keeping any reserves that were accumulated.