Roulette Ideas

YES. It is beatable. Not every session but most.

Here is interesting, the 20 value.
So to loose the original 100 divided capital, so as to play one session try to win +4 Bet.
We have to play 19 other Session to try to win. And this all in Flat Bet without other betting value.

So if Session "A" from Morning is lost, retry new on Evening the next.
And is full impossible, to lost 10 day per 2 session on day, to lost this capital.

Because, it's don't say, player should use to engage the rest of Capital by lost one session. By lost one session, here player should stop, and come back on night, to make new try.

Yes FreeRoulette. This all is correct!

here I add new time the Sumary to playing:

QuoteIn summary, after each session, one adds one's winnings to the capital Bankroll, which, thus increased and still divided by 20, results each time in larger bets to be placed in the next
session—this is what is called "snowballing."
If, in a session, one loses all twenty bets, without managing to win back the four coins, then one has fallen below the initial capital of one hundred francs, minus the reserves;—then one starts over with a second capital of one hundred francs,
with which one proceeds in the same manner, and so on.
You play at least two sessions per day, one in the morning and one in the evening—so by winning
four progressive stakes per session for ten days, the initial capital of one hundred francs will
have reached the amount of:

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Ok here we have ou'r 36 first spin. Or 12x 3 figure.
Blue color = is first spin from each figure. So this is used only to verify, if player should Black or Red Side from Figure start so this don't be Bet.
here my first 12x3 Figure from Spin, I don't Bet it; I use it only before start to control.
First 3 = Figure 5 = Start with R. Side. here player need only to bet the second and third spin.
For me self, I use coded Figure = Fig 5 to R-R-R. spin Or Black side figure = obtain code 1.
So Code 5-6-7-8 = Red Side figure and 1-2-3-4 are used on Black side figure.

Original system From Sextius, it was a player in Era 1870. So on this time nothing Roulette game have right to use it, Casino or Tripot in France was closed (Under King Louis Phillipe on 1.1.1839 to 1933.) Here Sextius going to play in Monte-carlo (Monaco) which was out of french Territory.
Or another player going to play in Germany or Spa (Belgium).
So Sextius; it have only use the amount of chance. So.
Series of 1 = each 2 spin.
Series of 2 = each 4 spin
Series of 3 = each 8 spin
""""""""" 4 = each 16
""""""""" 5 = each 32
""""""""" 6 = each 64
""""""""" 7 = each 128
""""""""" 8 = each 256
""""""""" 9 = each 512
""""""""" 10 = each 1024
""""""""" 11 = each 2048
""""""""" 12 = each 4096
""""""""" 13 = each 8192
""""""""" 14 = each 16384
""""""""" 15 = each 32768
...

French_cunning_Fox it seem there are actually three different ideas being discussed.

### 1. The Original 1875 Snowball System

The book starts with a total bankroll of 1,000 francs divided into ten separate capitals of 100 francs each.

For one attack:

* Capital = $100
* Divide by 20
* Bet size = $5

Flat bet $5 until either:

* Net profit reaches +$20 (4 units), or
* The entire $100 capital is lost

If the session wins:

* Capital becomes $120
* New bet size = $120 ÷ 20 = $6

The next session is played at $6 per bet until a profit of $24 is reached.

Only $20 is added to the working capital:

* $120 + $20 = $140

The extra $4 goes into a reserve fund.

The process repeats:

* $140 ÷ 20 = $7
* Win $28
* Add $20 to capital
* Put $8 into reserve

This is the "snowball" effect described in the book.

### 2. Failure According to the Original Book

If the player loses the entire capital before reaching the profit goal, that attack is considered a failure.

The book does not continue from the reduced bankroll.

Instead, the player starts a fresh attack using the next 100-franc capital.

Example:

Attack #1 = Lost

Start Attack #2 with a fresh $100.

The author assumes that eventually one successful snowball run will more than compensate for previous failed attacks.

### 3. French_cunning_Fox's Concern

French_cunning_Fox raised an interesting question.

Suppose we do not follow the book exactly.

Suppose we start with:

* $100 capital
* Lose one session

Now bankroll = $80.

What should happen next?

### Option A - Continue From $80

Simply continue.

* $80 ÷ 20 = $4 per bet

Play the Snowball system using the reduced bankroll.

This follows the logic of bankroll management but is not how the original book handled failures.

### Option B - Recover Back To $100 First

Instead of snowballing from $80, use the smaller bet size:

* $80 ÷ 20 = $4

Play until a profit of $20 is achieved.

Bankroll returns to:

* $80 + $20 = $100

Then restart the Snowball progression from the beginning.

This preserves the original structure of the progression.

### Option C - Use Another Capital

Follow the original idea more closely.

If the first attack falls from $100 to $80 and is considered failed, take another $20 from a fresh 100-dollar capital and restore the attack bankroll back to $100.

The player is effectively treating the bankroll as ten separate attacks rather than one continuously shrinking bankroll.

### Another Concern

French_cunning_Fox also pointed out that gain progressions can create a situation where a player builds a large profit but later loses it all.

His example was a player reaching +600 units and eventually giving everything back.

Because of this, he prefers the idea of securing profits and playing with "casino money" whenever possible rather than continuously exposing all accumulated gains.

### My Question

If we are playing a modern version of the Snowball system with a starting bankroll of $100 and the bankroll falls to $80:

Which approach makes the most sense?

A) Continue from $80

B) Recover back to $100 before snowballing again

C) Treat the loss as a failed attack and restart with a fresh $100 capital

I'm interested in hearing how others would handle this situation.

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So I follow my explain:

It is also clear that, no matter what system a player uses on the even-money bets in roulette, the chances of winning or losing will remain 48.7% or 51.3%—and here I am specifically referring to the percentage chance of winning or losing when the ball lands on zero.
Because with the d'Alembert betting progression, at some point, as we bet larger amounts, we'll be quite happy that the 0, when it comes up, gives us a little bonus.

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