is it possible to transform each old Martingale from lost to Progress Gain?

Started by French_cunning_Fox, Jun 19, 2026, 11:44 AM

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French_cunning_Fox

Hello everyone!

A Martingale, are a betting form, if player have lost Bet or any time hes Bet.
A progression, so as he name explain, progress with Gain so with money win from Casino.

Basis Martingale D'Alembert (old Mathematicien) which have found: 1-2-3-4-5...
So if lost 1 unit, player should next net 2 unit, then 3 units, then 4, and so long time each bet is lost. And by winning one bet, as example: -1-2-3-4-5 +6, the next Bet, the player Go down to 5 units then 4 units...
So here the player have lost -1-2-3-4-5 = -15 unit, by winning +6 (-15 -+6 = -9) here player need to win +5 +4 +3 +2 +1, so to win a serial of 6 to coming out, after lose a serial 5, or in multiple other way, so as example to 9x bet to win 6x, or to 12x bet win 9x, and each time, the player win +1 unit, by still standing on win phases. So player can win only +8 unit, by a serial from 8 which coming out.

And to wining progression.
here the player should win +1 +1 before betting 2 unit, so +1+1+2+3+4 = +11 from serial 5 Winning hands.

If, for example, a player wins 70 out of 100 bets and loses 30 or 28, what is their actual net gain?
here with lose 30, is integrated the coming of 0.
on 100 Game hands, the Croupier, can reach 2-3x to coming out 0.

To Verify this, is useful to use my old number from Bad-Homburg, from date 06-06-2026. (French Roulette Table)

French_cunning_Fox

Attachment is awaiting approval.

Well, even when I play, I like to know, what came out as luck or chance before launching into a game.
And here the eternal players all ask the same question, just seeing his little series.
How to win your series on both sides. As much red as black to can play it?.

This is called Figure. As example:
R-R-R-R-B-B Figure from 6 Spin.
6 spin = 64 Combination of different figure; so it have 1/64 chance to find the figure which coming out, before it start it.

I like more 3 spin Figure, this have only 8 combination of different figure. so as: R-R-R; R-B-R; R-B-B  and R-R-B + same wo start with first spin as Black color.

French_cunning_Fox

So I follow my explain:

It is also clear that, no matter what system a player uses on the even-money bets in roulette, the chances of winning or losing will remain 48.7% or 51.3%—and here I am specifically referring to the percentage chance of winning or losing when the ball lands on zero.
Because with the d'Alembert betting progression, at some point, as we bet larger amounts, we'll be quite happy that the 0, when it comes up, gives us a little bonus.

Translated with DeepL.com (free version)

French_cunning_Fox

Attachment is awaiting approval.
Ok here we have ou'r 36 first spin. Or 12x 3 figure.
Blue color = is first spin from each figure. So this is used only to verify, if player should Black or Red Side from Figure start so this don't be Bet.
here my first 12x3 Figure from Spin, I don't Bet it; I use it only before start to control.
First 3 = Figure 5 = Start with R. Side. here player need only to bet the second and third spin.
For me self, I use coded Figure = Fig 5 to R-R-R. spin Or Black side figure = obtain code 1.
So Code 5-6-7-8 = Red Side figure and 1-2-3-4 are used on Black side figure.

Original system From Sextius, it was a player in Era 1870. So on this time nothing Roulette game have right to use it, Casino or Tripot in France was closed (Under King Louis Phillipe on 1.1.1839 to 1933.) Here Sextius going to play in Monte-carlo (Monaco) which was out of french Territory.
Or another player going to play in Germany or Spa (Belgium).
So Sextius; it have only use the amount of chance. So.
Series of 1 = each 2 spin.
Series of 2 = each 4 spin
Series of 3 = each 8 spin
""""""""" 4 = each 16
""""""""" 5 = each 32
""""""""" 6 = each 64
""""""""" 7 = each 128
""""""""" 8 = each 256
""""""""" 9 = each 512
""""""""" 10 = each 1024
""""""""" 11 = each 2048
""""""""" 12 = each 4096
""""""""" 13 = each 8192
""""""""" 14 = each 16384
""""""""" 15 = each 32768
...

FreeRoulette

These are the steps as I understand them.

1. Wait for a 3-spin pattern where the first two spins are the same color.
2. Bet that color for the next 2 spins.
3. Follow the progression: 1, 1, 2, 3, 4.
4. Advance the progression after each win.
5. Reset to 1 unit after any loss.
6. Quit the session when you're up 4 units or after 5 attempts.
7. Never increase your bet to recover losses.

One step 5, for a reset, do we keep playing the same color or do we restart the system looking for the pattern again in step 1.