## Playing on repeating Groups of Pleins/straights

Started by winkel, Sep 14, 2022, 11:38 PM

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#### winkel

This idea is developed on a certain way to play Markov-Chains.

I don´t wanna discuss the original ways of M-Chains, because this got nothing to do with it.

One way to play Markov-Chains is to wait till we find two neighbours with a difference of maximum 2 parted by a 3rd number wwhich is far from those numbers.

e.g. 21 33 22 we would bet
e.g. 30 31 32 we would dismiss

the bettting-rule says: bet those two number and the two left and right.
e.g. from above 19 20 21 22 23 24

This is a waiting game and it fails naturally.

My idea but thinks the other direction:

If we have 19 and 23 (doesn´t matter if back to back or some spins apart) we have one "result" and the second "trigger" of the rules descriped above.
So I thought we could bet on the first trigger. (e.g. the 22)

But we don´t know the first trigger. we just know it can be at max two numbers in each direction of the 2nd trigger. which is: 22 23 24 20 21
and two each side of the result: 19 20 21 17 18

This is the idea. But I thought this too complicated and it must be easier to bet.

So I just said: If we find 19 and then 23 just bet 23 plus 4 numbers each side.
19 20 21 22 23 24 25 26 27 that´s 9 numbers to bet.

(If we find 23 and then 19 we bet: 15 16 17 18 19 20 21 22 23)

I´ll be back tomorrow

#### VLS

Welcome & thank you for your sharing!
🤗 👍

Email/Paypal: betselectiongmail.com
-- Victor

#### winkel

Thanks Victor.

How can I upload pictures?

#### winkel

Some examples:
all spins from yesterday 2022-09-14

from Osnabrück Table 1

30
3
11
3      this qualifies for 36 0 1 2 3 4 5 6 7 (if you get to the edges 0 or 36 just preceed)
2      and wins

from Wiesbaden Table 5

22
33
31 this qualifies for 27 28 29 30 31 32 33 34 35
6
29 and wins

and Wiesbaden Table 7

19
27
19 this qualifies for 15 16 17 18 19 20 21 22 23
7
13
22  and wins

#### winkel

some calculations

you bet 9 numbers, so you may place bets 4 times.
your average win should be 1 in 4

I calculate
bet -9
win +36
chip remains on winning number -1
chip Tronc -1
total +25 net.

#### winkel

what happens on a win?

That is your decision and you shoulod try some virtual bets to see what is possible.

spins from yesterday Hannover Table 4

15
4
5  this qualifies for 1 2 3 4 5 6 7 8 9
35
2  win and it qualifies for 35 36 0 1 2 3 4 5 6
6  win and it qualifies for 2 3 4 5 6 7 8 9 10
2  win and it qualifies for 35 36 0 1 2 3 4 5 6
0  win and it qualifies for 33 34 35 36 0 1 2 3 4
now a dealers change. Do you trust the trend or the hand.
check dealers if they throw in your favour or if they throw crazy (for your game)

#### winkel

Tisch 3 (AR)
Z   S   Z   R
16:14:49   28
16:12:15         19
16:11:02         27
16:09:45         18
16:08:17   22
16:07:02         27
16:05:47         18
16:04:30   15
16:02:16         12
16:01:07         1

this a tricky one:
read from bottom to top
12
15 qualifies 11 12 13 14 15 16 17 18 19
18 wins and qualifies 14 15 16 17 18 19 20 21 22
27
22 wins and qualifies 18 19 20 21 22 23 24 25 26
18 wins and qualifies 14 15 16 17 18 19 20 21 22
27 a new qualifier!!!! for 23 24 25 26 27 28 29 30 31 we bet both
19 wins and qualifies 15 16 17 18 19 20 21 22 23
28 wins and qualifies 24 25 26 27 28 29 30 31 32

Now is the question how to handle this situation:
bet both qualifiers again and again?
bet only the last (newest)
bet the old winning

a possible solution is this way:
you bet and win a qualifier.
a new qualifier comes up
bet the old one once again and then change to the new one
or risk the double bet only once

#### VLS

Quote from: winkel on Sep 15, 2022, 01:20 PM

Thanks Victor.

How can I upload pictures?

Hello & good day dear Winkel, you can use full editor mode for doing so.

Please notice there is now an "Add files" button on the quick reply form as a shortcut for it.

Thanks again for your sharing!

Email/Paypal: betselectiongmail.com
-- Victor

#### FreeRoulette

Hey Winkel,

A) e.g. 21 33 22 we would bet

0, 2, 14, 35, 23, 4, 16, 33, 21, 6, 18, 31, 19, 8, 12, 29, 25, 10, 27, 00, 1, 13, 36, 24, 3, 15, 34, 22, 5, 17, 32, 20, 7, 11, 30, 26, 9, 28

B) e.g. 30 31 32 we would dismiss

0, 2, 14, 35, 23, 4, 16, 33, 21, 6, 18, 31, 19, 8, 12, 29, 25, 10, 27, 00, 1, 13, 36, 24, 3, 15, 34, 22, 5, 17, 32, 20, 7, 11, 30, 26, 9, 28.

Do we bet option A because 33 and 21 are next to each other on the wheel?

#### winkel

sorry @FreeRoulette I didn´t notice this post.